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Use 40 samples point if possible. (1) Sampling (b) Choose the gain of … In this circumstance we will proceed as follows: x2 = 2*sin(2*pi*t*257.321e3); x2 = x2 + randn(size(x2))*std(x2)/db2mag(SNR); In order to increase this, Julian Bell overclocked the RPi3’s I2C bus in order to increase its sampling rate. Generate 1024 samples of a chirp sampled at 1024 kHz. 2 ( ) = + 0.5cos 2 2500 200 0 10 sec( ( )) Note that this is known as a “chirp” signal. TheElementsofSmyle(TransceiverDesign) The condition for avoiding the slope overload is A > ∴ 1 = ∴ ωn = 25.6 × 103 rad /sec. Add white Gaussian noise. Estimate and display the instantaneous frequency of the signal. Use the fft and fftshift commands for this purpose. Generate a sinusoid with a 1000 Hz for 0.05 sec using a samplingrate of 8 kHz, a. Assignment 1 6 1.2 Assignment 1 Solutions 1. The message has bandwidth 10 kHz and average power 10 W. The carrier amplitude at the transmitter is 1 V. Assume the channel attenuates the signal power by a factor of 1000, i.e., 30 decibel (dB). Lecture: Sums of Sinusoids (of different frequency) Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. To become effective, the DDS-based generator requires a decent filter capable of an attenuation greater than 100 dB at about 250 kHz for a generated dc to 25 kHz CW signal frequency range. Figure 4.5: Avoiding aliasing in signal processing Assume that a sampling rate of 8000 samples/s will be used to generate a PCM signal. f=0.09"f s =0.09"1000! Note that Angle Modulated Systems - GATEstudy.com x2 = 2*sin(2*pi*t*257.321e3); x2 = x2 + randn(size(x2))*std(x2)/db2mag(SNR); Determine the frequency and amplitude of all product components and determine their normalized powers. The on-board codec of the DSK has a sampling rate of f s = 8 kHz and an anti-aliasing filter with cutoff frequency 3.6 kHz, which is 90% of f s /2 (Nyquist Frequency). fs = 512; % Sampling frequency (samples per second) dt = 1/fs; % seconds per sample. Generate 1024 samples of a chirp sampled at 1024 kHz. where B = 200 kHz and No = 10¡9 W/Hz. Generate 1024 samples of a 100.123 kHz sinusoid sampled at 1024 kHz. Using 100 observations, estimate the power spectrum using order 3, 4, 6, and 12th order AR models. StopTime = 0.25; % seconds. Reset the random number generator for reproducible results. = 2.822 x 10 6 x 3600 = 10.16 x 10 9 bits or 10.16 gigabits Ans. Determine the output SNR in a Delta modulation system for a 1 KHz sinusoid , sampled at 32 kHz , without slope overload , and followed by a 4 KHz post reconstruction filter . P. 5.15.20 : DM signal Part II : Maximum frequency : Given : A = 1V, fm = 10 kHz, fs = 1/Ts = 1/10 µ s = 100 kHz. In other words, the wave has a frequency of 0.09 of the sampling rate: Equivalently, there are samples taken over a complete cycle of the sinusoid These samples represent accurately the sinusoid because there is no other sinusoid that can produce the same samples! ANSWER: (d) 200 KHz. The second channel is a complex exponential with a frequency of 126 Hz. The component of the input x[n] suppressed by the discrete-time system simulated by this program is – Signal #2, the high frequency one (it is a low pass filter). For example, if the frequency deviation is 100 kHz, then a +5 V signal level (optionally +1 V on the 33600 Series) corresponds to a 100 kHz increase in frequency. The DDS is a 12-bit output, up to 180 MHz master clock sinewave generator with a 24-bit tuning word allowing 10.8 Hz/LSB frequency resolution. If I low-pass filter the PWM signal it should result in a pure sinusoid: A*cos(2*pi*60*t+phi) of 60 Hz, which is the reference signal to the pwm. Signal frequency range: 0 – 3400 Hz. The second channel is a complex exponential with a frequency of 126 Hz. It generates sine and clock outputs simultaneously at up to 100 MHz with 1.07 µHz resolution. Reset the … by a 4 volt peak cosine waveform with frequency 3 kHz. Specify the chirp so that it has an initial frequency of 50 kHz and reaches 100 kHz at the end of the sampling. Write a MATLAB program to implement the downsampling scheme, andplot the original signal and the downsampled signal versus the sample number,respectively. If you have 100 per cycle, then, at 10KHz, you would need a sample rate of 1MHz. It will have a flat spectrum from 2.5 kHz up to 4.5 kHz. (a) Make a frequency assignment for each of the eight possible 3-bit data combinations. Lower external signal levels produce less deviation and negative signal levels reduce the frequency below the carrier frequency. the Nyquist frequency and use the other 10% for roll-off. 024 68 10 • The discrete-time sinusoid shown in the figure has which can be obtain from, for example, either a 1 second sampled continuous-time sinusoid with f = 0.2 Hz or 1.2 Hz. Add Gaussian white noise to get an SNR of 10 dB. Generate 1024 samples of a chirp sampled at 1024 kHz. Humans can only hear up to about 20 kHz, so there was no need to test past this point. A sampling process is done by setting the sampling frequency f s to 1 kHz, and the number of samples N to 10. ANSWER: (d) 200 KHz. Generate 1024 samples of a chirp sampled at 1024 kHz. y1_1 = 10*sin(40*pi*t); %T1=1/20, yields the same sample as original one figure(1),subplot(2,1,1),plot(t,y1_1,'--b'); y1_2 = -10*sin(24*pi*t); %T1=1/12, yields the same sample as … The signal frequency is arranged to vary between 0 and 1000 Hz using an FP control. The sinusoid output is generated by sequentially activating these taps at a rate determined by the master clock signal. Name the waveform as Original Signal. Specify a sinusoid frequency of 200 Hz. 141) A 100MHz carrier is frequency modulated by 10 KHz wave. Reset the random number generator for reproducible results. Specify the chirp so that it has an initial frequency of 50 kHz and reaches 100 kHz at the end of the sampling. Derive the formula used. b. 2. The train is sampled at 2 kHz for 1.2 seconds. Add white noise. Generate another sinusoid, this one with a frequency of 257.321 kHz and an amplitude that is twice that of the first sinusoid. Explanation: Carrier frequency f c = 100MHz Modulating frequency f m = 5 KHz Frequency deviation Δf = 100 KHz Carrier swing of the FM signal = 2 * Δf = 2 * 100 = 200 KHz. The test sinusoid samples are rounded to a finite precision: Digitally sampled sinusoids do suffer from a certain amount of round-off error, but Matlab and Octave use double-precision floating-point numbers by default (64 bits). I Showed (via phasor addition rule) that the above sum can always be written as a single sinusoid of frequency f . 2000 KHz b. Generate 1024 samples of a 100.123 kHz sinusoid sampled at 1024 kHz. Using 100 observations, estimate the power spectrum using order 3, 4, 6, and 12th order AR models. f = sin(2*pi*100/1000 * [0:1023]); % 1024 samples of 100hz sampled at 1khz fd = f . (12 points) FHSS Consider an MFSK scheme with carrier frequency f c equal to 250 kHz, difference frequency f d equal to 25KHz, and M equal to 8 (L equal to 3 bits). Reset the random number generator for reproducible results. Generate 1024 samples of a chirp sampled at 1024 kHz. Set the frequency of the generator to a 12 MHz sinusoid (the carrier signal), the carrier frequency, and center it on the scope display. The low pass filter specifications to eliminate the images are less stringent for the second case. If the peak frequency deviation of the generated FM signal is three times the transmission a. Well, at 1 KHz, this many samples will "play" in 0.5 sec, and if they are playing a 10 Hz sinusoid, you'll get 5 sine waves out. Include the prototype sample rate in the function call. Generate a three-channel signal consisting of three different chirps sampled at 1 kHz for one second. Plot using the stem function. An analog signal contains frequencies up to 10 kHz s base fold s1 F 4 kHz < 5kHz 2 or F 8 kHz < 2F 10 kHz aliasing happe F =F kF 5 (1)4 1 ns al fo iase ld d kHz F (a) What range of sampling frequencies allow exact reconstruction of this signal from its samples? generate a digital code that best corresponds to the analog sample. 1. Reset the random number generator for reproducible results. fullscreen Expand The chirp has an initial frequency of 50 kHz and reaches 100 kHz at the end of the sampling. Reset the … Generate 1024 samples of a 100.123 kHz sinusoid sampled at 1024 kHz. To become effective, the DDS-based generator requires a decent filter capable of an attenuation greater than 100 dB at about 250 kHz for a generated dc to 25 kHz CW signal frequency range. The AD9106 TxDAC® and waveform generator is a high performance quad DAC integrating on-chip pattern memory (4096 × 12-bit) for complex waveform generation with a direct digital synthesizer (DDS). 2 ( ) = + 0.5cos 2 2500 200 0 10 sec( ( )) Note that this is known as a “chirp” signal. (a) rad/sec The frequency components of s(t) for positive frequencies are: (b) which consists of two sinusoidal components with frequencies f0 = 1 kHz and f1 =2 kHz. The PWM has a switching frequency of 5 kHz. Assume that the ratio of peak signal power to average quantization noise power at the output needs to be 30 dB. I have a signal from a PWM inverter that was sampled at 3,84 kHz. Answered: Image Analyst on 12 Oct 2015. generate a 10 kHz sinusoid sampled at 100 kHz. The sinusoids have different amplitudes and noise levels. By using direct digital synthesis (DDS) and precise phase-lock loop Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. You can hear, that the 38 kHz sine sampled at 48 kHz sounds exactly like 10 kHz: an effect of aliasing. The noiseless chirp has a frequency that starts at 20 kHz and increases linearly to 30 kHz during the sampling. 1. (10) The modulationindex is defined as β = kωAm ωm = peak frequency deviation modulating frequency (11) Example: fc = 1 kHz, fm = 100 Hz, fs = 80 kHz, β = 5-1-0.5 0 0.5 1 0 500 1000 1500 2000 s(t) Time in Samples-1-0.5 0 0.5 1 0 500 1000 1500 2000 m(t) Time in Samples 8-4 The first Hi , please I'm confused with the following time vectors t1 and t2 to generate 0.5 second duration sinusoid signal : Vector t1 has equally spaced samples at Ts intervals , but the signal x1 has duration equal to ( duration+Ts ) seconds , I checked x1 length . The following example generates multiple cycles and I am not sure how to get a single cycle. Sum of Sinusoidal Signals Time-Domain and Frequency-Domain Introduction I To this point we have focused on sinusoids of identical frequency f x (t)= N Â i=1 Ai cos(2pft + fi). Specify the number of harmonics to 7. The 9.8 kHz sine wave has an amplitude of 1 volt, the 14.7 kHz wave has an amplitude of 100 microvolts, and the 19.6 kHz signal has amplitude 30 microvolts. This can be achieved with a sixth-order Chebyshev and even a sixth-order Butterworth LP filter for a perfect in-band flatness. Assignment 1 4 ... Lathi 6.1-1: The bandwidth of … 100 KHz c. 105 KHz d. 200 KHz. The frequencies of the sinusoids are 1 kHz, 10 kHz, and 20 kHz. Generate a two-channel signal sampled at 3.2 kHz for 10 seconds and embedded in white Gaussian noise. 2 Answers: Q2.1 The output sequence generated by running the above program for M = 2 with x[n] = s1[n]+s2[n] as the input is shown below. Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. The chirp has an initial frequency of 50 kHz and reaches 100 kHz at the end of the sampling. The pwm signal is feeding an induction motor. Reshape the signal into a three-dimensional array such that the time axis runs along the third dimension. * exp(+i*50/1000 * [0:1023])); figure(); plot(20*log(abs(fft(f)))); figure(); plot(20*log(abs(fft(fd)))); figure(); plot(20*log(abs(fft(fu)))); Generate 1024 samples of a chirp sampled at 1024 kHz. The horizontal axis must be scaled appropriately to represent the interval (-π, π). What would you expect to happen? Set the generator to internal AM sinewave modulation with a frequency of 10 KHz. Now suppose you generate a finite number of samples, say 500. Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. Plot four cycles of this signal. * exp(-i*50/1000 * [0:1023])); fu = f . Reset the random number generator for reproducible results. 3. To sample a signal in MATLAB, generate a time vector at the appropiate rate, and use this to generate the signal. Plot using the stem function. For example: % Sample the sinusoid x = sin (2 pi f t), where f = 2 kHz. % Let x1 be the signal sampled at 10 kHz. Generate 1024 samples of a 100.123 kHz sinusoid sampled at 1024 kHz. Reset the random number generator for reproducible results. This signal is sampled at a rate of 30 samples per second by an analog-to-digital converter to create a digital signal x[n]. Solution : Given that, f m = 1 kHz, f s = 32 kHz, BW = 4 kHz ... in a DM system for a 1 kHz sinusoid, sampled at 32 kHz, without slope overload and followed by a 4 kHz post construction filter ... A m = 10 maximum-length shift register is used to generate the pseudorandom sequence in a DS spread-spectrum system. Design a decimator to change the sampling rate to 4 kHz with specificationsbelow: b. Compute the maximum-to-minimum differences of the rows, specifying the dimension equal to 2 with the dim argument. Plot four cycles of the signal. Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. Specify the chirp so that it has an initial frequency of 50 kHz and reaches 100 kHz at the end of the sampling. For example: % Sample the sinusoid x = sin(2 pi f t), where f = 2 kHz. 100 MHz Frequency Generator Overview The National Instruments PXI-5404 is a 100 MHz frequency generator packaged in 1-slot PXI module. The signal is sampled at 44.1 kHz. A simplified example of the RCDAC, as shown in IX 5 kHz Sinusoid sampled at 20 kHz 0 0.5 1 1.5 2 32.5 0 time (x 10-3) amplitude VIII 1 kHz Sinusoid-10000 -5000 0 5000 10000 frequency (Hz) amplitude X 5 kHz Centered M-Blob-2000 -1000 0 1000 2000 frequency (Hz) amplitude XI DC-Centered M-Blob 0 0.5 1 1.5 2 32.5 0 time (x 10-3) amplitude XII 5 kHz Square Wave Transcribed image text: (a) Generate a 10-kHz sinusoid sampled at 100 kHz. To sample a signal in MATLAB, generate a time vector at the appropiate rate, and use this to generate the signal. Set the frequency of the generator to a 12 MHz sinusoid (the carrier signal), the carrier frequency, and center it on the scope display. (1).In MATLAB, generate a 10kHz sinusoid sampled at 100kHz. Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. Determine the THD, the power at the harmonics, and the corresponding frequencies. Determine the THD, the power at the harmonics, and the corresponding frequencies. (10) The modulationindex is defined as β = kωAm ωm = peak frequency deviation modulating frequency (11) Example: fc = 1 kHz, fm = 100 Hz, fs = 80 kHz, β = 5-1-0.5 0 0.5 1 0 500 1000 1500 2000 s(t) Time in Samples-1-0.5 0 0.5 1 0 500 1000 1500 2000 m(t) Time in Samples 8-4 If the 20 kHz signal is under-sampled at 30 kHz, find the aliased frequency of the signal. What would you expect to happen? (i) Determine the maximum amplitude of a 1-kHz input sinusoid for which the delta modulator does not show slope overload. Generate 1024 samples of a 100.123 kHz sinusoid sampled at 1024 kHz. Generate a two-channel signal sampled at 3.2 kHz for 10 seconds and embedded in white Gaussian noise. Fig. Then, use subplot to plot the magnitude and phase spectrum of this signal in the interval (−, ). Hello, I need help generating a single cycle of a sinewave at a particular frequency and sampling rate. Reshape the signal into a three-dimensional array such that the time axis runs along the third dimension. that is, fc = 100 kHz. I For example, we use the following MATLAB fragment to generate a sinusoidal signal: fs = 100; tt = 0:1/fs:3; xx = 5*cos(2*pi*2*tt + pi/4); I The resulting signal xx is a discrete-time signal: I The vector xx contains the samples, and I the vector tt … Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. Add Gaussian white noise to get an SNR of 10 dB. sinusoid sampled at samples/second. A signal is sampled at 8 kHz and is quantised using 8 bit uniform quantizer. This results in a 10 ms sampled signal. Now suppose you generate a finite number of samples, say 500. Reset the random number generator for reproducible results. Use the fft and fftshift commands for this purpose. Also plot the spectrum of the decimated signal in … Let our signal be a sinusoid x(t) containing an unknown frequency that lies in the range from 1 Hz to 2 Hz. Generate a sinusoid with a frequency of 500 Hz for 0.1 sec using a. sampling rate of 8 kHz, a. design an interpolation and decimation processing algorithm to changethe sampling rate to 22 kHz. The quantizing step size is 250 mV. To illustrate them consider a sinusoid x ( t) = 4 cos (2 πt ). Its sampling period, according to the Nyquist sampling rate condition, is as the maximum frequency of x ( t) is Ω max = 2 π. We let Ts = 0.01 (sec/sample) to obtain a sampled signal xs ( nTs) = 4 cos (2 πnTs) = 4 cos (2 πn/100), a discrete sinusoid of period 100. In this problem, we study the performance of Burg's algorithm for a simple signal: a sinusoid in noise. a. A sampling process is done by setting the sampling frequency f s to 1 kHz, and the number of samples N to 10. Therefore, † the Nyquist sampling rates for g1(t) is 200 kHz, sampling interval Ts = 1=200k = 5„s † the Nyquist sampling rates for g2(t) is 300 kHz, sampling interval Ts = 1=300k = 3:33„s. The signal consists of a 100 Hz fundamental with amplitude 2 and three odd-numbered harmonics at 300, 500, and 700 Hz with amplitudes 0.01, 0.005, and 0.0025. 1. Determine the minimum value of step size to avoid slope overload. 2. Determine granular noise power N0, if the voice signal bandwidth is 3.5 kHz. 3. Assuming signal to be sinusoidal, calculate signal power So and signal to noise ratio (SNR). 4. Fewer than two samples would not do this. significance. It takes 100 samples to make this sine wave, right? We will use the internal modulator of the generator to examine AM time waveforms and spectra. 141) A 100MHz carrier is frequency modulated by 10 KHz wave. Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. Specify the chirp so that it has an initial frequency of 50 kHz and reaches 100 kHz at the end of the sampling. Note that the amplitude of the signal on the scope drops by 2:1 so that the pk-pk voltage will be 2V when the modulation level, =1. Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. The signal frequency is arranged to vary between 0 and 1000 Hz using an FP control. 1. Initially specify the generated pulse as a prototype. The ADS1115 had a variable sampling rate that goes up to 860 SPS. ... in a DM system for a 1 kHz sinusoid, sampled at 32 kHz, without slope overload and followed by a 4 kHz post construction filter ... A m = 10 maximum-length shift register is used to generate the pseudorandom sequence in a DS spread-spectrum system. The minimum sampling rate (Nyquist rate) = 10K samples/sec. Generate 1024 samples of a chirp sampled at 1024 kHz. The first channel consists of a concave quadratic chirp with instantaneous frequency 100 Hz at t = 0 and crosses 300 Hz at t = 1 second. As a result, our samples are far more precise than could be measured acoustically in the physical world. [1000 samples/sec * 0.1 sec = 100 samples]. Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. The first channel consists of a concave quadratic chirp with instantaneous frequency 100 Hz at t = 0 and crosses 300 Hz at t = 1 second. The following code plays out three consecutive sines: at 100, 1000, 10 000 and 38 000 Hz and displays their spectra. Reset the … If x(t) is the input to the sampler, the output is x(nT), where T is called ... signals ranging from 10 kHz to 80 kHz with a sampling frequency Fs = 40 kHz. Generate 1024 samples of a 100.123 kHz sinusoid sampled at 1024 kHz. δ = 265 mV. The first channel of the signal is a 124 Hz sinusoid. The signal is sampled using the following three sampling frequencies: • f s Create a signal sampled at 10 kHz. Add white Gaussian noise such that the signal-to-noise ratio is 40 dB. The amplitude is equal to the row index. Generate a sinusoidal signal sampled at 1 kHz for 0.3 second and embedded in white Gaussian noise of variance 1/16. IX 5 kHz Sinusoid sampled at 20 kHz 0 0.5 1 1.5 2 32.5 0 time (x 10-3) amplitude VIII 1 kHz Sinusoid-10000 -5000 0 5000 10000 frequency (Hz) amplitude X 5 kHz Centered M-Blob-2000 -1000 0 1000 2000 frequency (Hz) amplitude XI DC-Centered M-Blob 0 0.5 1 1.5 2 32.5 0 time (x 10-3) amplitude XII 5 kHz Square Wave Generate another sinusoid, this one with a frequency of 257.321 kHz and an amplitude that is twice that of the first sinusoid. The first channel of the signal is a 124 Hz sinusoid. Also plot the spectrum of this signal in the interval (-π, π). Explanation: Carrier frequency f c = 100MHz Modulating frequency f m = 5 KHz Frequency deviation Δf = 100 KHz Carrier swing of the FM signal = 2 * Δf = 2 * 100 = 200 KHz. A signal is sampled at 8 kHz and is quantised using 8 bit uniform quantizer. Reset the random number generator for reproducible results. This results in a 10 ms sampled signal. For the case of a square wave at 1 kHz with a duty cycle less than or equal to 10% which is sampled at 10 kHz, you are misunderstanding the input. The test sinusoid samples are rounded to a finite precision: Digitally sampled sinusoids do suffer from a certain amount of round-off error, but Matlab and Octave use double-precision floating-point numbers by default (64 bits). The two sample minimum allows the samples to capture the oscillatory nature of the sinusoid. Create a signal sampled at 10 kHz. Top is the frequency plot for a 100 Hz signal sampled at 1 KHz and up-sampled to 3 KHz. The horizontal axis must be Set the generator to internal AM sinewave modulation with a frequency of 10 KHz. t = (0:dt:StopTime-dt)'; % seconds. (b) Decimate this signal by a factor of 2. Illustrate the amplitude spectrum and normalized power spectrum on a two-sided frequency axis. The signal consists of a 100 Hz fundamental with amplitude 2 and three odd-numbered harmonics at 300, 500, and 700 Hz with amplitudes 0.01, 0.005, and 0.0025. If it is an external DAC,you can forget I2C/TWI or SPI because you could not get all the bits through the pipe in 1us (16 clock cycles). EXAMPLE 4.29. Generate 1024 samples of a chirp sampled at 1024 kHz. Create a superposition of three sinusoids, with frequencies of 9.8, 14.7, and 19.6 kHz, in white Gaussian additive noise. Specify the number of harmonics to 7. 2000 KHz b. As a result, our samples are far more precise than could be measured acoustically in the physical world. 1. Bottom is the same 100 Hz signal sampled at 1.5 KHz and up-sampled to 3 KHz. Reset the random number generator for reproducible results. Reset the … Determine the output SNR in a DM system for 1 kHz sinusoid, sampled at 32 kHz without slope overload and followed by a 4 kHz post construction filter. First you would need to decompose your waveform into a Fourier series to figure out what the amplitudes of the component harmonics are. Create a signal consisting of three noisy sinusoids and a chirp, sampled at 200 kHz for 0.1 second. m =10KHz – 5. (Consider an angle modulation signal )=6 [2×103+ ... 12.A message signal with bandwidth 10 KHz is Lower-Side Band SSB ... 20.c(t) and m(t) are used to generate an FM signal. The chirp has an initial frequency of 50 kHz and reaches 100 kHz at the end of the sampling. Generate a three-channel signal consisting of three different chirps sampled at 1 kHz for one second. Create a matrix where each row is a 100 Hz sinusoid sampled at 1 kHz with a different amplitude. x 10-3-1-0.8-0.6-0.4-0.2 0 0.2 0.4 0.6 0.8 1 time (seconds) Figure 11.3: A sinusoid at 7.56 kHz and samples taken at 8 kHz. First, generate a sinusoid with period equal to 25 samples. 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